The reason this is so complicated is because of a mathematical principle called Factorials.
它所以如此复杂,是因为这一数学原理。
Instead of factorial time, it takes linear time.
它不是时间, 而是线性时间。
So the n minus k will become b minus a factorial.
所以 n 减去 k 将变成 b 减去一个。
If this was 7 over 7 minus 2 factorial we would have 7 times 6.
如果这是 7 除 7 减 2 ,们将有 7 以 6。
For those who remember from math class, that is seven factorial.
对于那些记得数学课上人来,这是七个。
So times lambda to the k k over k factorial.
所以以 lambda 到 k k 。
So you end up with 1 times lambda k over k factorial.
所以你最终得到 lambda k 1 倍于 k 。
Divided by 2 factorial times e to the minus 9 power.
除以 2 e 负 9 次方。
And as you'll see it's actually 2 factorial ways that it can happen.
正如您将看到,它实际上可以通过两种方式发生。
You may have heard that there is a function generalizing the factorial to real and even complex inputs, the gamma function.
您可能听过有一个函数将推广到实数甚至复数输入,即伽马函数。
This video by Michael DiFranco about extending the factorial offers another great example of a lesson with good motivation along the way.
Michael DiFranco 制作这段关于扩展视频提供了另一个很好例子,明了一路上具有良好动机课程。
If this had 3 we would do 3 factorial, and I'll show you how that can happen.
如果它有 3,们会做 3 个,会告诉你这是如何发生。
5 factorial is 5 times 4 times 3 times 2 times 1.
5是5以4以3以2以1。
Once again, you'll have to know that 0 factorial is equal to 1.
再一次,你必须知道 0 等于 1。
So k factorial could be written as k times k minus 1 factorial.
所以 k 可以写成 k 以 k 减 1 。
And here we can make a little bit of a simplification because what's k divided by k factorial?
在这里们可以稍微简化一下,因为 k 除以 k 是多少?
And we just showed that this is equal to lambda to the kth power over k factorial times e to the minus lambda.
们刚刚证明这等于 lambda k 次方以 e k 以负 lambda。
So this could be rewritten as k times k minus 1 factorial.
所以这可以改写为 k k 减 1 。
So we could rewrite n factorial using the same trick up here.
所以们可以在这里使用相同技巧重写 n 。
To account for that, you divide out by the extent to which you've overcounted, the number of permutations of four items which looks like four factorial.
为了解释这一点, 您可以除以多算程度,即四个项目排列数量, 看起来像四个。
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